Question

Ow many grams of calcium phosphate can be produced when 89.3 grams of calcium chloride reacts with excess sodium phosphate? unbalanced equation: cacl2 + na3po4 → nacl + ca3(po4)2

Answer 1

CaCl2 = 40 + 35.5*2 = 111 g/mol
Ca3(PO4)2 = 40*3 + (31+16*4)*2 = 310 g/mol

89.3 g CaCl2 = 89.3/111 = 0.8045 mol CaCl2

Balanced equation:
3CaCl2 + 2Na3PO4 --------> 6NaCl + Ca3(PO4)2

3 moles CaCl2 produce 1 mol Ca3(PO4)2
Therefore 0.8045 mol CaCl2 produces 1/3 * 0.8045
= 0.2682 mol Ca3(PO4)2
= 0.2682 mol * 310 g/mol
= 83.1 g Ca3(PO4)2

Ans: 83.1 g