Formula for the volume of cone is
![(1)/(3) \pi r^2h](https://img.qammunity.org/2019/formulas/mathematics/middle-school/htwk8rpzuedj79x07hu0pnuhpf7sk3yb7f.png)
Where r= radius of the cone
h = height of the cone
The value of pi is 3.14
Given volume of larger cone is 131 cm^3
Volume of larger cone =
![(1)/(3) \pi r^2h](https://img.qammunity.org/2019/formulas/mathematics/middle-school/htwk8rpzuedj79x07hu0pnuhpf7sk3yb7f.png)
131 =
![(1)/(3) \pi 5^2h](https://img.qammunity.org/2019/formulas/mathematics/high-school/q7zepa0jm03c8akvis2l6xmnw3ke3qm5s8.png)
Solve for h
131 = 26.1667 *h
So h= 5 cm
The height of bigger cone = 5cm
Now we find the volume of smaller cone
Two cones similar so the sides are in proportional
![(radius(small))/(radius(large))= (height(small))/(height(large))](https://img.qammunity.org/2019/formulas/mathematics/high-school/1vzu2yedwca45zytx3amlbhur8eebppe8b.png)
![(2)/(5) =( height of small)/(5)](https://img.qammunity.org/2019/formulas/mathematics/high-school/ql1fzmurgu48e6nub1inoam3c8rujwhlj8.png)
Height of smaller cone = 2cm
volume of smaller cone =
![(1)/(3) \pi 2^2*2](https://img.qammunity.org/2019/formulas/mathematics/high-school/rio0haey358g7uzrumvwhclc5bhjf3sq46.png)
= 8.38cm^3