Question

Maria drops a stone from the top of a building. the stone falls 4.9 meters in the first second, 14.7 meters in the second second, and 24.5 feet in the third second, regardless of its weight. how many feet would an object fall in the tenth second?

Answer 1

The stone would fall approximately 112.21 feet in the tenth second.

Step-by-step explanation:

The distance fallen by an object in free fall can be calculated using the equation d = 1/2 * g * t², where d is the distance fallen, g is the acceleration due to gravity, and t is the time elapsed.

In this case, the stone falls 4.9 meters in the first second, 14.7 meters in the second second, and 24.5 meters in the third second.

From this information, we can determine that the distance fallen in each additional second will be 4.9 meters greater than the previous second.

Therefore, the stone would fall 34.3 meters in the tenth second.

Converting this to feet, the object would fall approximately 112.21 feet in the tenth second.

Answer 2

The distance fallen, s, of a freely falling object is given by the equation . . .

s = 1/2 gt², where g is the acceleration due to gravity.

s = (9.8/2)(t²) = 4.9t²

distance fallen in tenth second = total distance fallen in tenth second - total distance fallen in ninth second . . .

or, s(10) - s(9)

= 4.9(10²) - 4.9(9²) = 93.1 ft