Answer:
8 m.
Explanation:
The instantaneous displacement is

and to find
from
to
we integrate

since this integral is the area is the under the graph, the displacement
is the area under the graph of velocity vs. time graph.
Now having said that, let us calculate the area of the graph from 2 seconds to 6 seconds:

The area under the graph is 8, that means the displacement from 2 seconds to 6 seconds is 8 meters.