Question

In the game of​ roulette, a player can place a ​$66 bet on the number 66 and have a startfraction 1 over 38 endfraction 1 38 probability of winning. if the metal ball lands on 66​, the player gets to keep the ​$66 paid to play the game and the player is awarded an additional ​$210210. ​ otherwise, the player is awarded nothing and the casino takes the​ player's ​$66. what is the expected value of the game to the​ player? if you played the game 1000​ times, how much would you expect to​ lose?

Answer 1

if you played 1000 times there is a possibility of winning 380 times which could give you $79,879,800 if you played on number 66 each time.