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Solve for x. 5/2x+3=4/x

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\text{The domain:}\\2x+3\\eq0\ \vee\ x\\eq0\\\\D:x\in\mathbb{R}-\{-1.5,\ 0\}


(5)/(2x+3)=(4)/(x)\ \ \ |\text{cross multiply}\\\\5x=4(2x+3)\\\\5x=8x+12\ \ \ |-8x\\\\-3x=12\ \ \ \ |:(-3)\\\\x=-4\in D

Answer: x = -4

User Cristian Hantig
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