Question

A 2.00−L sample of water contains 150.0 μg of lead. Calculate the concentration of lead in ppm.

Answer 1

Given the volume of water sample = 2.00 L

Mass of lead = 150.0 μg

When we say that a solution is 1 ppm in concentration, it means that there is one part of solute per million parts of the solution.

One ppm = 1 mg solute/L solution

The concentration of lead in ppm:

150.0 μg ×
`(1 mg)/(1000 μg)` ×
`(1)/(2.00 L)`

= 0.075 ppm