1 Answer

Bigmeister · Answer 1 · 2019-09-16T11:34:05+0000

The given hyperbola is a vertical hyperbola, with centre (h,k) =(1,-2) , and vertices are (1,-6),(1,2).

So we have h =1, k =-2, and k+a =2

That gives a = 4

And the equation of asymptotes are

$y=-(4)/(3)x-(2)/(3),(4)/(3)x- (2)/(3)=\pm(4)/(3)(x-1)}+2$

Therefore

(a)/(b) =(4)/(3)

Substituting the value of a and solving for b

b=3

Required equation is

((y+2)^2)/(9) -((x-1)^2)/(16) =1

Please log in or register to add a comment.