Question

Find the first six terms of the sequence.

a1 = 4, an = 2 • an-1
serious answer only or you will be reported

Answer 1

Answer: 4,8,16,32,64,128

Step-by-step explanation:-

Given: The first term of sequence=
`a_1=4`

The given explicit rule for nth term is

`a_n=2\cdot a_(n-1)`

Now, the second term =
`a_2=2\cdot a_(2-1)=2\cdot a_(1)=2(4)=8`

The third term =
`a_3=2\cdot a_(3-1)=2\cdot a_(2)=2(8)=16`

The fourth term =
`a_4=2\cdot a_(4-1)=2\cdot a_(3)=2(16)=32`

The fifth term =
`a_5=2\cdot a_(5-1)=2\cdot a_(4)=2(32)=64`

The sixth term =
`a_6=2\cdot a_(6-1)=2\cdot a_(5)=2(64)=128`

Hence, the first six terms of the sequence are 4,8,16,32,64,128