Slopes of perpendicular segments are always negative reciprocal of each other. Or, we can say product of slopes of perpendicular segments is always -1.
Given the slope of PQ is 5/2.
So the slope of its perpendicular segment should be -2/5.
Finding slopes of given options:-




From above calculations, it is clearly visible that slopes of RS and VW are negative reciprocal of slope of PQ.
So, correct answers are RS and VW.