Question

How can one fourthx − 3 =one halfx + 8 be set up as a system of equations?

a 4y + 4x = −12
2y + 2x = 16

b 4y − x = −12
2y − x = 16

c 4y + x = −12
2y + x = 16

d 4y − 4x = −12
2y − 2x = 16

Answer 1

The answer is B hope this help u

Answer 2

4y − x = −12

2y − x = 16

Explanation:

Given :
`(1)/(4)x-3=(1)/(2)x+8`

We get,

`(1)/(4)x-3=y` ..........(1)

`(1)/(2)x+8=y` .....(2)

Multiply equation (1) by 4 , we get,

`x-12=4y`

or
`4y-x= -12`

Now, multiply equation (2) by 2 , we get,

`x+16=2y`

or
`2y-x= 16`

Hence, option B is correct.