The formula for the Binomial Theorem with a power 6 is as:
![(x+y)^6=x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6](https://img.qammunity.org/2019/formulas/mathematics/high-school/ulz9i5ry63u17e0ay66fyttrjwqe1zx0i0.png)
Thus, if we plug in 20 for x and 5 for y, our first term itself will be
which is much greater than 256 and thus it will not make any sense to use
to approximate 256 using the binomial theorem.
Also, it will not make any sense to use
as that has no power and we know that Binomial Theorem makes use of Power. Anyway,
.
Our best bet here would be to use the equation with power 8:
![(x+y)^8=x^8+8x^7y+28x^6y^2+56x^5y^3+70x^4y^4+56x^3y^8+28x^2y^6+7xy^7+y^8](https://img.qammunity.org/2019/formulas/mathematics/high-school/f7nk49h95kgiz6qaczohc8scbw6d9svi78.png)
and have
and
which will give us
![(1+1)^8=1^8+8(1)^7(1)+28(1)^6(1)^2+56(1)^5(1)^3+70(1)^4(1)^4+56(1)^3(1)^8+28(1)^2(1)^6+7(1)(1)^7+(1)^8 =256](https://img.qammunity.org/2019/formulas/mathematics/high-school/e1g094dbv5s63arrz43mxbzlihoczr6qjt.png)