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The weekly incomes of a large group of executives are normally distributed with a mean of $2,000 and a standard deviation of $100. what is the z-score for an income of $2,100? g

User MindFold
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Let X be the weekly incomes of a large group of executives. The weekly incomes of a large group of executives follows Normal distribution with mean $2000 and standard deviation $100.

μ =2000, σ =100

We have to find z score for income $2100 i.e x=2100

Z =
(x-mean)/(standard deviation)

=
(2100 - 2000)/(100)

Z = 100/100

Z = 1

The z score for income $2100 is 1

User Shane Gadsby
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