Question

What is the perimeter of a triangle with vertices located at (1,4), (2,7), and (0.5), rounded to the nearest hundreth?

Answer 1

`\boxed {\text {Length = }√((X_2-X_1)^2 + (Y_2-Y_1)^2)}`

The three lengths are:

`\text {Length 1 = }√((2-1)^2 +(7-4)^2) = √(10)`

`\text {Length 2 = }√((2-0)^2 +(7-5)^2) = √(8)`

`\text {Length 3 = }√((1-0)^2 +(4-5)^2) = √(2)`

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`\text{Perimeter = } √(10) + √(8) + √(2) = 7.40 \text { (nearest hundredth)}`

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Answer: 7.40 units