The given problem is stated as below:
3√3q = 27
√3q = 9
(√3q)^ = 9^
(^ stands for squared )
3q = A
Therefore we have,
A = 9^
or, A = 81
Again it is given that,
3q = A
or, 3q = 81.
or, q = 81/3 = 27
q = 27
As per the problem q = B,
therefore we can conclude that B = 27
So by solving the problem we get the final answer as below:
A = 81 and B =27