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Determine if the vectors v1 = (2, −1, 2, 3), v2 = (1, 2, 5, −1), v3 = (7, −1, 5, 8) are linearly independent vectors in r4 .

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Vectors are linearly independent if there doesn't exist a non-trivial linear combination which returns the zero vector. So, we must see if we can find three coefficients
(a,b,c)\\eq(0,0,0) such that



av_1+bv_2+cv_3 = (0,0,0,0). We have



av_1 = (2a, -a, 2a, 3a)



bv_2 = (b, 2b, 5b, -b)



cv_3 = (7c, -c, 5c, 8c)


So,
av_1+bv_2+cv_3 = (2a+b+7c, -a+2b-c, 2a+5b+5c, 3a-b+8c)


This linear combination returns the zero vector if



2a+b+7c = 0


-a+2b-c = 0


2a+5b+5c = 0


3a-b+8c = 0


This system admits the only trivial solution a=b=c=0, so the vectors are linearly independent.

User Juna
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