Question

The perimeter of the parallelogram WXYZ is 2 square root of 26 + _____units.

Answer 1

`|ZW|=|YX|=√(26)\to2|ZW|=2|YX|=2√(26)\\\\|ZY|=|WX|=4\to2|ZY|=2|WX|=2\cdot4=8`

The perimeter of the parallelogram WXYZ is:

`P=2√(26)+8`

Answer 2

2√26+8 units

Explanation:

Perimeter of the parallelogram will be the sum of all the sides of the parallelogram.

Note that the opposite sides of a parallelogram are equal hence

|WZ| = |XY| and |WX| = |ZY|

Given |WZ| = √26, |XY| = √26

To get |WX|, we will take the distance between the point W and X

|WX| = √{(2-(-2)}²+(2-2)²

|WX| = √4²+0²

|WX| = √16

|WX| = 4

Therefore |WX| = |ZY| = 4

Perimeter of the parallelogram = |WZ| + |XY| + |WX| + |ZY|

= √26+√26+4+4

= 2√26+8

The perimeter of the parallelogram is 2√26+8 units