Answer:
1. HL: Hypotenuse-leg theorem.
Step by step explanation:
We have been given two right triangles and we are asked to find how our triangles are congruent to each other.
Since we know that if one leg and hypotenuse of a right triangle is congruent to leg and hypotenuse of another triangle then both triangles are congruent. We will use Pythagorean theorem to prove our answer.
In
,

In
,

We have been given that
and
, so by the definition of congruence EM=TN and AM=OT.
Upon using substitution we will get,

Since we are given that EM=TN,

Subtracting
from both sides of equation we will get,


We can see that our angle is congruent by SSS congruence. Therefore, we can see that
by Hypotenuse-leg theorem and first option is the correct choice.