Question

Given y=(2x+3)2, choose the standard form of the given quadratic equation

Answer 1

`y=(2x+3)^2 = 4x^2 +12x +9`

Taking 4 out from first two terms, we will get

`y=4(x^2+3x)+9`

Now we divide the coefficient of x by 2 and add and subtract the square of the result, we will get

`y=4(x^2+3x+(9)/(4)-(9)/(4))+9`

Distributing 4

`y=4(x+(3)/(2))^2+9-9`

Cancelling 9

`y=4(x+(3)/(2))^2`

And that's the required standard form.