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Solve for x.

−ax + 4b > 9



1) x > the quantity 4 times b minus 9 all over a

2) x < the quantity 9 minus 4 times b all over a

3) x < the quantity negative 4 times b plus 9 all over negative a

4) x > the quantity 4 times b plus 9 all over negative a

1 Answer

0 votes

The answer is the first option: 1)
x> the quantity
4 times
b minus
9 all over
a

The explanation is shown below:

1. To solve this problem you must pply the following proccedure:

2. Move the term
4b to the left member. As the variable is negative, multiply the expression by
-1 and change the direction of the sign:


-ax+4b>9\\ (-1) -ax>9-b4 (-1)\\ x>(ab-9)/(a)

User Paul Kozlovitch
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