Question

a skateborder traviling at 7.0m/s/s rolls to a stop at the top of a ramp in 3.0 seconds what is the skateborder's acceleration?

Answer 1

-2.33 m/s^2

Step-by-step explanation:

initial speed u = 7m/s

final speed v= 3s

acceleration a = (v-u)/t

a= -7/3= -2.33 meter per second square.