Question

A two-digit locker combination is made up of nonzero digits and no digit is repeated in any combination.

Event A= the first digit is 1

Event B= the second digit is even

If a combination is picked at random with each possible locker combination being equally likely, what is P(A and B) expressed in simplest form?

Answer 1

I'm doin the quiz now and I think the answer is A. 1/18

Explanation:

Answer 2

`|\Omega|=9\cdot8=72\\ A\cap B=\{(1,2),(1,4),(1,6),(1,8)\}\\ |A\cap B|=4\\\\ P(A\cap B)=(4)/(72)=(1)/(18)\Rightarrow \text{A}`