Take a look at the function
![y+2=- (2)/(3)x+4](https://img.qammunity.org/2019/formulas/mathematics/middle-school/n6lc0ajj86pq3k782lu4ast2wkra7r5x59.png)
. You can simplify it to
![y=- (2)/(3)x+2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/2dopp6v2g6l6l6cq6twpri00912izlyh32.png)
. If x=0, then y=2 and when y=0, x=3. You obtain two points (0,2) and (3,0) that lie on the line
![y+2=- (2)/(3)x+4](https://img.qammunity.org/2019/formulas/mathematics/middle-school/n6lc0ajj86pq3k782lu4ast2wkra7r5x59.png)
.
Since
![y+2\le - (2)/(3)x+4](https://img.qammunity.org/2019/formulas/mathematics/middle-school/5zpyl62fz4mf3vpt2gewwqsd2maxkmyods.png)
, the line
![y+2=- (2)/(3)x+4](https://img.qammunity.org/2019/formulas/mathematics/middle-school/n6lc0ajj86pq3k782lu4ast2wkra7r5x59.png)
should belong to the shaded area.
Now take point (0,0). Since
![0+2\le- (2)/(3)\cdot 0+4](https://img.qammunity.org/2019/formulas/mathematics/middle-school/vx6831n5oij3faexizlkou9ep7580o59c6.png)
, you can conclude that point (0,0) belongs to the shaded area.Using all these thoughts, you can make a conclusion that the correct choice is B.