Question

A ship is moving with a constant acceleration of 36km/hr2 in a fixed direction speeds up from 12 km/hr to 18km/hr. Find the distance traveled by the ship in this period

Answer 1

v square - u square = 2as. here s=distance
here v squared= 18 squared=324
u squared=12 squared=144
324-144=2×36×s
180=72s
hence distance=2.5