Question

Surjithayer10 said:

9x+2y=6
divide by 2
3x+y=3
y=-3x+3
it is in the form y=mx+c

How did you get the 3x+y=3 into y=-3x+3 ?

Answer 1

That is incorrect from the beginning because 9 divided by 2 is not 3. If you are putting that original equation into slope-intercept form you begin by subtracting 9x from both sides. 2y = -9x + 6. Divide both sides by 2 and you have an equation solved for y:
`y=- (9)/(2)x+3`. That is slope-intercept form of the original equation, which is a line in standard form