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What is the molarity of a solution that contains 30 grams of naoh in 500 milliliters of solution?
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What is the molarity of a solution that contains 30 grams of naoh in 500 milliliters of solution?

User Timothy Meade
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2 Answers

7 votes

Answer: 1.5 M

Step-by-step explanation:

User Drakes
by
8.1k points
5 votes
Molar mass NaOH = 39.997 g/mol

number of moles solute:

n = mass of solute / molar mass

n = 30 / 39.997

n = 0.00075 moles of NaOH

Volume in liters:

500 mL / 1000 => 0.5 L

Therefore :

M = moles of solute / volume ( L )

M = 0.00075 / 0.5

M = 0.0015 mol/L
User Max Niagolov
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8.0k points
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