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Two cylinders are similar. The radius of cylinder A is 5.6 inches. The radius of cylinder B is 1.4 inches. If the height of cylinder B is 4 inches, what is the height of cylinder A? 8.2 inches 8.2 square inches 16 inches 16 square inches

User Eugene
by
9.4k points

2 Answers

2 votes

Answer:

C. 16 inches is correct

Explanation:

We are given the dimensions of the cylinders as,

Cylinder A: Radius = 5.6 inches and Height = x inches

Cylinder B: Radius = 1.4 inches and Height = 4 inches

Now, as the cylinders are similar, the ratio of the measurements will be equal.

So, we get,


(R_(A))/(R_(B))=(H_(A))/(H_(B))

i.e.
x=(5.6* 4)/(1.4)

i.e.
x=(22.4)/(1.4)

i.e. x = 16

Thus, the height of the cylinder A is 16 inches.

Hence, option C is correct.

User Tbc
by
7.7k points
3 votes

If two cylinders are similar, then all their linear measurements have equal ratios. Hence:



(r_A)/(r_B) =(h_A)/(h_B).


Since the radius of cylinder A is 5.6 inches, the radius of cylinder B is 1.4 inches and the height of cylinder B is 4 inches, you can find the height of cylinder A:



(5.6)/(1.4) =(h_A)/(4).


Use the cross multiplication:



1.4h_A=5.6\cdot 4,\\ 1.4h_A=22.4,\\ h_A=(22.4)/(1.4) =16 in.


Answer: the height of cylinder A 16 inches.

User Amirhosein Rostami
by
8.5k points