Question

the vertex of this parabola is at (-4 -1). when the y-value is 0, the x-value is 2. What is the coefficient of the squares term in the parabola’s equation?

Answer 1

The correct answer is A

Answer 2

The standard form for this parabola is
`x=a(y-k)^2+h` because this is a sideways-opening parabola. Our h and k values for the vertex are (-4, -1). And it goes through (2,0). We just need to solve for the a. Filling in accordingly,
`2=a(0+1)^2-4` so 2 = a - 4. a = 6. A above.