Answer:
Δ ABC congruent to Δ AED by SAS only
Explanation:
* Lets revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and
including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ
≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles
and one side in the 2ndΔ
* Lets solve the problem
- In the two triangles ABC and AED
∵ m∠BAC = m∠EAD ⇒ given from the figure
∵ m∠CBA = m∠DEA ⇒ given
∵ The sum of the measures of the interior angles of a triangle is 180°
∴ m∠ACB = m∠ADE
- In Δ ABC and Δ AED
∵ AC = AD
∵ BC = ED
∵ m∠ACB = m∠ADE ⇒ including angle between the two sides
∴ Δ ABC ≅ Δ AED by SAS
- We can't prove from the given that AB = AE
* Δ ABC congruent to Δ AED by SAS only