Question

PLEASE HELP!!! Find the real number solutions for the equation. x^2 - 3x + 8 = 0

A. 0

B. 2

C. 1

D. Cannot be determined

Answer 1

To find the real number solutions for the equation, we need to use the quadratic formula:

`x = \frac{ - b( + - ) \sqrt{ {b}^(2) - 4ac } }{2a}`
(pardon the (+-), it is supposed to be a plus/minus sign) from the equation

`a {x}^(2) + bx + c`
In this case, we have a = 1, b = -3, c = 8.

`- ( - 3)`

`\frac{ - ( - 3)( + - ) \sqrt{ {( - 3)}^(2) - 4(1)(8) } }{4(1)} \\ (3( + - ) √(9 - 36) )/(4)`
Since 9 - 36 is a negative number and we cannot square root a negative number, the answer is D. Cannot be determined.

Answer 2

`x^(2) -3x+8=0`


`\Delta= 3^(2) -4*8*1=9-32=-23\ \textless \ 0`

Answer D
Cannot be determined