The given fraction is:
![(y+5)/(2y+10)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/tbdrzr5hvt1tbi6l2f6rrhu3195yxa6exh.png)
We cannot take anything common from the numerator but from the denominator we can take out 2 as common because 2 is a factor of both the terms i.e. 2y and 10.
2y + 10 can be written as 2y +2(5) which can further be written as 2(y+5)
So, our fraction now becomes:
![(y+5)/(2(y+5))](https://img.qammunity.org/2019/formulas/mathematics/middle-school/3ow5rabsfieqablj0vfho9q0aj2m5tdy1h.png)
y+5 occurs in both the numerator and denominator and thus be cancelled out leaving behind:
Therefore, the given fraction in lowest term is equal to 1/2. So option B is the correct answer