85.2k views
1 vote
What was the equation of the graph below before it was shifted to the right 1 unit? (equation was g(x)=(x-1.5)^3-(x-1.5))

a. g(x)=(x-.5)^3
b. g(x)=(x-2)^3-(x-2)
c. g(x)=(x)^3
d. g(x)=(x-0.5)^3-(x-0.5)

ps: answer is worth 2 points on apex

User Dexity
by
5.4k points

2 Answers

3 votes

Answer:

d

Explanation:

User Drewster
by
6.0k points
4 votes
If graph of the function y=f(x) was shifted to the right 1 unit, then you got new function y=f(x-1).
Reversly, if you have the function
g(x)=(x-1.5)^3-(x-1.5) that is obtained by shifting to the right 1 unit, then the initial function was


g(x+1)=(x+1-1.5)^3-(x+1-1.5), \\ g(x+1)=(x-0.5)^3-(x-0.5).
Answer: Correct choice is D.
User Ojrask
by
5.6k points