Question

What is the probability that a group of 5 random digits will contain at least 3 odd digits?

46370, 55170, 53480, 49126, 89212, 75292, 67291, 88241, 37808, 38154

A.) 4/5

B.) 2/5

C.) 1/5

D.) 3/5

Answer 1

B.) 2/5

Explanation:

There are a total of 10 sets of random numbers with 5 digits within each set. What you are looking for is how many sets contain exactly 3 odd digits. By observing each set, you will find that 4 sets will contain 3 odd digits (these sets being 55170, 75292, 67291, and 38154). The rest of the sets don't include exactly 3 odd digits, so you can discard of those other sets.

So if we have 10 sets of numbers and 4 of these sets contain 3 odd digits, we can set up the fraction: 4/10

After simplifying the fraction, you get your answer of 2/5

Also I did this quiz on A-P-E-X and the answer turned out to be 2/5, but I also gave an explanation to any one who is curious on how the answer was 2/5 :)

Hope this helps!