Question

For the function h defined as h(x) = nx² + 28, n is a constant and h(3) = 1. What is the value of h(-6) ?​

Answer 1

Explanation:

Step One

The first step is to find the value of n.

h(x) = n(x) + 28

h(3) = 1

That means that 1 is on the left and wherever there is an x on the right, it will have a value of 3

Step Two

Substitute values

1 = n(3) + 28

Step 3

Solve

1 = 3*n + 28 Subtract 28 from both sides

1 + - 28 = 3n Combine

-27 = 3n Divide both sides by 3

-27/3 = 3n/3

- 9 = n

Step 4

Let x = - 6 on the right side of the original equation.

h(-6) = 3*-6 + 28

h(-6) = -18 + 28

Answer

h(-6) = 10