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5 votes
5 votes
find the three postive consecutive integers such that the product of the smallest and the largest is 17 more than 3 times the median intger

User SuperAadi
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2 Answers

28 votes
28 votes

Answer:

find the three postive consecutive integers such that the product of the smallest and the largest is 17 more than 3 times the median intger

User Steve Chaloner
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3.2k points
15 votes
15 votes

Answer: 5, 6, 7

Explanation:

Let three positive consecutive integers equal to x, x+1, x+2

Hence,


\displaystyle\\x(x+2)-3(x+1)=17\\x^2+2x-3x-3=17\\x^2-x-3-17=17-17\\x^2-x-20=0\\x^2-5x+4x-20=0\\x(x-5)+4(x-5)=0\\(x-5)(x+4)=0\\x-5=0\\x-5+5=0+5\\x=5\in\ (x > 0)\\x+4=0\\x+4-4=0-4\\x=-4\\otin\ (x > 0)\\5+1=6\\5+2=7

User Hindol
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