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What is keq for the reaction 2so2(g) + o2(g) 2so3(g)? apex?

User Amitwdh
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2 Answers

2 votes

Answer: The
K_(eq) for the reaction is

K_(eq)=([SO_3]^2)/([SO_2]^2[O_2])

Step-by-step explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric coefficients. It is represented by
K_(eq)

For a general chemical reaction:


aA+bB\rightarrow cC+dD

The
K_(eq) is written as:


K_(eq)=([C]^c[D]^d)/([A]^a[B]^b)

For the given chemical reaction:


2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

The
K_(eq) is represented as:


K_(eq)=([SO_3]^2)/([SO_2]^2[O_2])

Hence, the equilibrium constant for the reaction is given above.

User Hamit
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6 votes
The keg for the reaction
2 SO2(g) + O2(g) → 2 SO3(g) is

Keg = [SO3]^2/ {(SO2)^2 ( O2)}

Keg (equilibrium constant) is the ratio of of equilibrium concentration of the product raised to the power of their stoichiometric coefficient to the equilibrium concentration of the reactant raised to the power of their stoichiometric coefficient.

User SKK
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