The scale factor is given by:

The relationship of the areas for this case is given by:

Rewriting we have:

The relation of volumes is:

Where,
V1: small solid volume
V2: volume of the large solid
Clearing V2 we have:

Substituting values:
Answer:
The ratio of their corresponding areas is:
36/169
The volume of the larger solid is:
4394 in ^ 3