Answer:
Option C. is the correct option.
Explanation:
We will try to factorize each option
a)

= 4[(2x²)² - 1] = 4[(2x²-1)(2x²+1)] [since (a²- b²)=(a-b)(a+b)]
b) 2x(y³-4y²+5y)
= 2xy(y² - 4y + 5)
c) 3x(9x²+ 1) It is in the factored form.We can not factorize it further.
d) 5x²- 17x + 14
= 5x²- 10x - 7x + 14 = 5x(x - 2) - 7(x -2) = (5x - 7)(x - 2)