Factor x^3-7x^2-5x+35

asked Jul 6, 2019 107k views

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$x^3-7x^2-5x+35=x^2(x-7)-5(x-7)=(x-7)(x^2-5)\\\\=(x-7)[x^2-(\sqrt5)^2]=(x-7)(x-\sqrt5)(x+\sqrt5)$

$Used:\\a^2-b^2=(a-b)(a+b)$

Jewel answered Jul 12, 2019

by Jewel

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