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Find two numbers with a sum of 20 and a difference of 14.

1 Answer

1 vote
Let these two numbers be
x and
y. Clearly,
x\\eq y, because
|x-y|=0\\eq14. Let's assume
x<y. Then


\begin{cases}x+y=20\\y-x=14\end{cases}


From the second equation, we can obtain
y=x+14, so substituting for
y in the first equation gives



x+(x+14)=2x+14=20\implies 2x=6\implies x=3

which means
y=3+14=17.
User Eelco Hoogendoorn
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