Question

How many molecules are there in 15.7 L of chlorine gas at STP

Answer 1

for plato, its 4.2241 * 10^23

Step-by-step explanation:

Answer 2

Hello!

We have the following information:

Knowing that for each mole of substance we have 6.02 * 10²³ molecules, it is known that in STP (Standard Temperature and Pressure) one mole of any gas equals 22.4 L, then:

22.4 L ----------------- 6.02*10²³ molecules
15.7 L ----------------- y molecules


`(22.4)/(15.7) = (6.02*10^(23))/(y)`


`22.4*y = 15.7*6.02*10^(23)`


`22.4y = 9.4514*10^(24)`


`y = (9.4514*10^(24))/(22.4)`


`y = 4.219375*10^(23)\:\to\:\boxed{\boxed{y \approx 4.22*10^(23)\:molecules}}\end{array}}\qquad\checkmark`

I hope this helps. =)