Question

375ml of a 0.455m sodium chloride solution is dilluted with 1.88l of water. what is the new concentration in molarity

Answer 1

Answer : The new concentration will be, 0.0757 M

Solution :

According to the dilution law,

`M_1V_1=M_2V_2`

where,

`M_1` = molarity of NaCl solution = 0.455 M

`V_1` = volume of NaCl solution = 375 ml = 0.375 L

`M_2` = new concentration = ?

`V_2` = volume of new concentration after dilution with water = 0.375 + 1.88 = 2.255 L

Now put all the given values in the above law, we get the new concentration.

`(0.455M)* 0.375L=M_2* (2.255L)`

`M_2=0.0757M`

Therefore, the new concentration will be, 0.0757 M