Question

Find the area of the rhombus. d1 = 12 m; d2 = 20 m

Answer 1

check the picture below.

so, assuming d1 and d2 are the diagonals of it, bearing in mind that the diagonals of a rhombus bisect each, cut in equal halves, then we can get the area of one of those 4 congruent triangles in the rhombus, notice each triangle has a base of 6 and a height of 10.


`\bf \stackrel{\textit{area of the 4 triangles}}{4\left[ \cfrac{1}{2}(6)(10) \right]}`

Answer 2

Answer:
`120\ m^2`

Explanation:

We know that the area of a rhombus is given by :-

`\text{Area}=(1)/(2)* d_1* d_2`, where
`d_1\ and \ d_2` are the diagonals of the rhombus.

Given:

`d_1=12\ m\\\\d_2=20\ m`

Then, the area of given rhombus will be :-

`\text{Area }=(1)/(2)*12*20\\\\\Rightarrow\text{area}=120\ m^2`

Hence, the area of rhombus =
`120\ m^2`