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Find the LCM of k^2 + 3k + 2 and 2k^2 + 14k + 20.

A. 2(k + 2)(k + 5)(k + 1)(k + 2)
B. (k + 2)(k + 5)(k + 1)
C. 2(k + 2)(k + 5)(k + 1)
D. (k + 2)

2 Answers

5 votes

Answer:

C

Explanation:

User Heinrisch
by
8.2k points
5 votes

Answer:

C. 2(k +2)(k +5)(k +1)

Explanation:

The LCM will be the product of unique factors.


(k^2 + 3k + 2)=(k+1)(k+2)\\(2k^2 + 14k + 20)=2(k+2)(k+5)

The unique factors are 2, (k+1), (k+2), (k+5), so the LCM is their product:

2(k+1)(k+2)(k+5) . . . . matches choice C

User Ignasi Barrera
by
8.0k points