Question

FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl

How many grams of NaCl could you make with 2.43306 g of FeCl3?

g NaCl (use 5 sig figs

Answer 1

2.6299

Step-by-step explanation:

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Answer 2

2.6299 g NaCl

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Stoichiometry

• Reading a Periodic Table
• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

[RxN} FeCl₃ + 3NaOH → Fe(OH)₃ + 3NaCl

[Given] 2.43306 g FeCl₃

Step 2: Identify Conversions

[RxN] 1 mol FeCl₃ = 3 mol NaCl

Molar Mass of Fe - 55.85 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of Na - 22.99 g/mol

Molar Mass of FeCl₃ = 55.85 + 3(35.45) = 162.2 g/mol

Molar Mass of NaCl - 22.99 + 35.45 = 58.44 g/mol

Step 3: Stoichiometry

1. Set up:
   `\displaystyle 2.43306 \ g \ FeCl_3((1 \ mol \ FeCl_3)/(162.2 \ g \ FeCl_3))((3 \ mol \ NaCl)/(1 \ mol \ FeCl_3))((58.44 \ g \ NaCl)/(1 \ mol \ NaCl))`
2. Multiply/Divide:
   `\displaystyle 2.62986 \ g \ NaCl`

Step 4: Check

Follow sig fig rules and round. We need 5 sig figs (instructed).

2.62986 g NaCl ≈ 2.6299 g NaCl