Final answer:
To find two consecutive negative integers whose product is 110, set up the equation x(x+1) = 110. Solve the resulting quadratic equation to determine the integer values -11 and -10.
Step-by-step explanation:
To find two consecutive negative integers whose product is 110, let's assume the first integer is x. The second consecutive integer will be x+1. We can set up the equation: x(x+1) = 110. Expanding the equation, we have x^2 + x = 110. Rearranging the equation, we get x^2 + x - 110 = 0. Now, we can solve this quadratic equation using either factoring, completing the square, or using the quadratic formula.
If we factor the quadratic equation, we find (x + 11)(x - 10) = 0. So, x = -11 or x = 10. However, since we need two negative integers, the value of x is -11.
Therefore, the two consecutive negative integers with a product of 110 are -11 and -10.
Learn more about Consecutive Negative Integers