Question

What is the vertical asymptote(s) for y=x^2+2x/x^2+5x-6?

Answer 1

The vertical asymptotes exist where the denominator goes to 0. That means we have to factor it to find the trouble spots.
`x^(2) +5x-6` factors easily into (x - 1)(x + 6), telling us that x = 1 and x = -6 by the zero product property. Therefore, the vertical asymptotes for this rational function are at x = 1 and x = -6