Question

A 20.00 ml sample of a solution of sr(oh)2 is titrated to the equivalence point with 40.03 ml of 0.1159 n hcl. what is the molarity of th sr(oh)2 solution?

Answer 1

The molarity of Sr(OH)2 solution is = 0.1159 M

calculation
write the equation for reaction
that is, Sr(OH)2 +2HCl→ SrCl2 + 2 H2O

then finds the mole of HCl used

moles = molarity x volume
=40.03 x0.1159 = 4.639 moles

by use of mole ratio between Sr(OH)2 to HCL which is 1 :2 the moles of Sr(OH)2 is therefore = 4.639 x1/2 = 2.312 moles

molarity of Sr(OH)2 is = moles / volume

=2.312 /20 =0.1159 M