Question

What is the change in enthalpy for the single replacement reaction between solid zinc and Cs2SO4 in solution to produce cesium and ZnSO4?

Zn + Cs2SO4 → 2Cs + ZnSO4

Given:

Cs2SO4(aq):ΔHf °= –1400 kJ

ZnSO4(aq):ΔHf °= –1063 kJ


2463 kJ


–2463 kJ


337 kJ


–337 kJ

Answer 1

337KJ Is the answer so good luck

Answer 2

ΔHo(reaction) = the sum of the enthalpy (heat) of formation of products - the sum of the enthalpy (heat) of formation of reactants:
ΔHo(reaction) = ΣHof(products) - ΣHof(reactants)

1(-1063kJ) - [1(-1400kj)
-1063 +1400 kJ

ΔHo(reaction) = +337kJ