Question

The length of a rectangle is two feet greater than twice its width. If the perimeter is 25 feet, find the width.”

Answer 1

The width of the rectangle is 3.5 feet.

Step-by-step explanation:

Let's assume that the width of the rectangle is 'w' feet.

According to the problem, the length of the rectangle is two feet greater than twice its width.

So, the length would be '2w + 2' feet.

The perimeter of a rectangle is given by the formula: P = 2(length + width).

Substituting the given values, we get: 25 = 2(2w + 2 + w).

Simplifying the equation, we get: 25 = 6w + 4. Subtracting 4 from both sides of the equation, we get: 21 = 6w.

Dividing both sides by 6, we get: w = 3.5.

Therefore, the width of the rectangle is 3.5 feet.

Answer 2

Hello!

To solve this problem, we will use substitution and a system of equations where L=length and w=width.

L=2+2w
2L+2w=25

We know that L equals 2+2w. Lets plug that into the bottom equation and find w.

2(2+2w)+2w=25
4+4w+2w=25
4+6w=25
6w=21
w=3.5

Now that we know w, we can find L.

L=2+7
L=9

We have found the width, but lets check our answer with the system of equations.

9=2+7
18+7=25

The width is 3.5 feet.

Hope this helps!